i'm trying to get an integer return from a def equation

Question

I'm trying to get it so my code will return just the integer of 2 in stead of 2.5464893461251985

def number_of_cookies(amount, height, radius):
    return(amount/10)/(radius*radius*3.14158*height)

print (number_of_cookies(40, 0.5, 1))
assert number_of_cookies(40, 0.5, 1) == 2
assert number_of_cookies(400, 0.5, 1) == 25
assert number_of_cookies(1200, 0.3, 1) == 127

Are you looking for [math.floor](https://docs.python.org/3/library/math.html?highlight=floor#math.floor) ? — Gabriel Devillers, Dec 19 '18 at 16:59
Any of `round()`, `floor division`, or casting to `int()` could work, depending on your ultimate purpose — G. Anderson, Dec 19 '18 at 17:00

score 0 · Accepted Answer · answered Dec 19 '18 at 16:59

0

def number_of_cookies(amount, height, radius):
    return int((amount/10)/(radius*radius*3.14158*height))

Setting to int will avoid the float precision you are seeing

answered Dec 19 '18 at 16:59

C.Nivs

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2
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Pika Supports Ukraine · Answer 2 · 2018-12-19T17:30:16.980

There are a couple of ways to do this. If you want it to become an integer, you can use int:

def number_of_cookies(amount, height, radius):
    return int((amount / 10) / (radius * radius * 3.14158 * height))

If there is a specified number of decimal places you want to round it to, you can use round:

def number_of_cookies(amount, height, radius):
    return round((amount / 10) / (radius * radius * 3.14158 * height), 0)

Finally, if you want to round it down, you can do this:

import math
def number_of_cookies(amount, height, radius):
    return math.floor((amount / 10) / (radius * radius * 3.14158 * height))

i'm trying to get an integer return from a def equation

2 Answers2