<script>
$(document).ready(function(){
$(".submit_modal1").click(function(e){
e.preventDefault();
id = this.id;
name = $("#fname_"+id).val();
email = $("#email_"+id).val();
phone = $("#phone_"+id).val();
upload_resume = $("#upload_resume_"+id).val();
$.ajax({
type:"POST",
data:{"id":id,"name":name,"email":email,"phone":phone,"upload_resume":upload_resume},
url:"<?php echo base_url(); ?>send",
success:function(data){
$("#send_hr").html(data);
}
});
$("#upload_resume_"+id).change(function(){
var file_data = $("#upload_resume_"+id).prop('files')[0];
var form_data = new FormData();
form_data.append('file', file_data);
$('#imgsss').html("<img src='<?php echo base_url(); ?>resource/loading.gif' />");
$.ajax({
url: '<?php echo base_url(); ?>upload_resume',
dataType: 'text',
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function(php_script_response){
$("#imgsss").html(php_script_response);
}
});
});
});
});
</script>
In this code, I trigger two events i.e. click and change
where I want to run $("#upload_resume_"+id).change(function(){});
inside $(".submit_modal1").click(function(e){})
. Is it possible to do it or is there any other way to trigger both event simulteniously. How can I do this ?Please help me.
Thank You