How can I divide an integer by an integer in C# and have a variable that has one or more decimal places?

Question

I tried this:

var b = 100 / 95;

and b is declared as an integer. But I would like to have a number with a decimal point.

How can I do this in C#?

Just googled "int by int division C#" and immediately found a dozens duplicate. — MakePeaceGreatAgain, Dec 21 '18 at 11:27
Is this some kind of reputation enhancing scheme? Ask easily googleable question, let mates answer it, give reputation to mates? — Dialecticus, Dec 21 '18 at 11:31
Maybe I am too suspicious but I don't buy making such a basic and duplicated question with 1400 rep — Cleptus, Dec 21 '18 at 11:53

score 3 · Accepted Answer · answered Dec 21 '18 at 11:26

With two integer operands, the C# overload resolution picks a version of the division operator that does integer division.

To make C# choose real division, you need to change the type of at least one of the operands into decimal, float, or double.

You can achieve this by casting, in the general case. In your specific case, you can also just change the literals involved:

 var b = 100m / 95;   // decimal
 var b = 100f / 95;   // float
 var b = 100.0 / 95;  // double

Use decimal if these are exact, human-made quantities (e.g. money). Use float or double if you are dealing with approximate, physical quantities (e.g. irrational numbers, physical constants, etc).

score 2 · Answer 2 · edited Dec 21 '18 at 11:47

2

You are doing an integer division which will ignore the fractional part of the division as it can not be stored in an int.

If you cast your variables to decimals you can store the fractional part of the division:

decimal b = (decimal)100 / (decimal)95;

edited Dec 21 '18 at 11:47

sedders123

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answered Dec 21 '18 at 11:27

Nick Mehrdad Babaki

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How can I divide an integer by an integer in C# and have a variable that has one or more decimal places?

2 Answers2