Getting screen pixels taking into account the scale factor

Question

I'm trying to get my screen size using python. I keep getting the incorrect value because my code is taking into account the scale factor. For example: My screen resolution is set to: 2736 x 1824. My scale factor is 200% so when I execute my code I get 1368 x 912.

import win32api
width = GetSystemMetrics(0)
height = GetSystemMetrics(1)
print('Width:', width)
print('Height:', height)

Is there any way I can get the resolution as shown in my windows settings without the scale factor? I want to be able to read 2736 x 1824.

Can you get the scale factor? If so, why not just use it to work out the actual resolution? — SiHa, Dec 21 '18 at 18:58
Possible duplicate of, useful or related [Number of pixels of screen python](https://stackoverflow.com/questions/41834451/number-of-pixels-of-screen-python) — chickity china chinese chicken, Dec 21 '18 at 19:31

score 4 · Answer 1 · answered Jan 07 '20 at 12:13

4

import ctypes

scaleFactor = ctypes.windll.shcore.GetScaleFactorForDevice(0) / 100

You can get the scale factor via shcore using ctypes. Then from this you can calculate the real resolution.

ie: scaleFactor 1.25 is 125%

answered Jan 07 '20 at 12:13

GO.exe

646
7
13

score 1 · Answer 2 · answered Dec 22 '18 at 05:42

1

Your application is not DPI aware. Windows has to lie to the application about the dimensions and magnify the GUI to fit the scale.

A quick fix:

import ctypes
ctypes.windll.user32.SetProcessDPIAware()

For an executable it is recommended to set DPI awareness in the manifest file.

answered Dec 22 '18 at 05:42

Barmak Shemirani

30,904
6
40
77

1

Do you know how to set it in the manifest file created by pyinstaller? Or is it an post-creation thing anyway? Thanks in advance. – Nummer_42O Jan 19 '20 at 17:43

Getting screen pixels taking into account the scale factor

2 Answers2

Linked