How to solve promise with await correct?

Question

Can someone tell me why await is not working here?

const Web3 = require('web3');

web3 = new Web3(new Web3.providers.HttpProvider("http://<ip>:8545"));

let accounts = (async () => await web3.eth.getAccounts())();

// await was not working, here I get a promise
console.log(accounts);

// if I wait with a timeout I get my accounts
setTimeout(() => console.log(accounts), 5000);

I tried this, but `await` is just allowed in functions, this is why I built this function around. — , Dec 22 '18 at 14:09
Does this answer your question? [How does javascript async/await actually work?](https://stackoverflow.com/questions/57160341/how-does-javascript-async-await-actually-work) — TylerH, Mar 03 '23 at 17:12

score 3 · Answer 1 · answered Dec 22 '18 at 14:12

3

Your console.log has to be inside the inline async function.

(async () => {
   accounts = await web3.eth.getAccounts()
   console.log(accounts);
}
)();

answered Dec 22 '18 at 14:12

Sumer

2,687
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24

pantyuhind · Accepted Answer · 2018-12-22T14:26:34.760

It doesn't work like that. An async function returns a promise. console.log outside async function will not wait for an await. You can only stop your code INSIDE an async function.

async function getData() {
    const answer = await web3.eth.getAccounts()
    console.log(answer) /* this console.log will be wait */
    return answer
}

getData().then(answer => console.log(answer))

If it'd works like that (holding code outside a function) It'd stop all process on a browser (like the alert function) and an user'd be have to wait too.

How to solve promise with await correct?

2 Answers2