Python function question about if-elif function

Question

Below is my answer for a question on Hackerrank.

However, when I run the code, 2 values appeared in the terminal. One of which is a None value. I'm not sure which line of code created this None value. Please advice. Thank you

Code:

def is_weird(num):
    if num % 2 == 1:
        print("Weird")
    elif num % 2 == 0 and 2 <= num <= 5:
        print("Not Weird")
    elif num % 2 == 0 and 6 <= num <= 20:
        print("Weird")
    elif num % 2 == 0 and num > 20:
        print("Not Weird")

N = int(input("Enter number: "))
print(is_weird(N))

Terminal output:

Enter number: 8
Weird
None

`print(is_weird(N))` -> `is_weird(N)`. Or don't print inside function, instead use `return`. — Austin, Dec 24 '18 at 05:35
you are trying to print response from your function, currently you are returning nothing. So only need to call the function instead of print `is_weird(N)` — Vikas Periyadath, Dec 24 '18 at 05:37

score 0 · Accepted Answer · answered Dec 24 '18 at 05:54

Python function returns None by default. In your case, the is_weird() function is returning None. So, when you enter 8 as input, your function prints "Weird" because of the print statement inside the function and then it returns None. This value gets printed because of the line print(is_weird(N))

Your isweird() function is equivalent to:

def is_weird(num):
    if num % 2 == 1:
        print("Weird")
    elif num % 2 == 0 and 2 <= num <= 5:
        print("Not Weird")
    elif num % 2 == 0 and 6 <= num <= 20:
        print("Weird")
    elif num % 2 == 0 and num > 20:
        print("Not Weird")
    return None

Python function question about if-elif function

1 Answers1