How to check the string has number and special characters in JavaScript?

Question

I have the below function to find the string contains numbers and special characters, but it was not working

let validateStr = (stringToValidate) => {
var pattern = /^[a-zA-Z]*$/;
if (stringToValidate&& stringToValidate.length > 2 && pattern.test(stringToValidate)) 
    {
    return false;
} else {
    return true;
}
};
validateStr("123$%^$") // I need the above function should return false.
validateStr("sdsdsdsd$%^$") // true
validateStr("sdsdsdsd") // true
validateStr("sdsdsdsd45678") // false
validateStr("$#*()%^$")//false
validateStr("123434333")//false

Possible duplicate of [Special character validation](https://stackoverflow.com/questions/16667329/special-character-validation) — Najam Us Saqib, Dec 26 '18 at 11:17
@Najamussaqib this is not duplicate, check the 4th function call, it was not working in your case .validateStr("$#*()%^$") check it with ur pattern. — parithi info, Dec 26 '18 at 11:25

Mamun · Accepted Answer · 2018-12-26T14:20:00.000

2

Your RegEx should be:

/[a-zA-Z]+[(@!#\$%\^\&*\)\(+=._-]{1,}/

Try the following way:

let validateStr = (stringToValidate) => {
  var pattern = /[a-zA-Z]+[(@!#\$%\^\&*\)\(+=._-]{1,}/;
  if ( stringToValidate && stringToValidate.length > 2 && pattern.test(stringToValidate)) {
    return true;
  } else {
    return false;
  }
};
console.log(validateStr("123$%^$"));      //false
console.log(validateStr("sdsdsdsd$%^$")); //true
console.log(validateStr("sdsdsdsd45678"));//false
console.log(validateStr("$#*()%^$"));     //false
console.log(validateStr("123434333"));    //false

edited Dec 26 '18 at 14:20

answered Dec 26 '18 at 11:48

Mamun

66,969
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for this case validateStr("sdsdsdsd45678") i need false to be return . – parithi info Dec 26 '18 at 14:03
1

@parithiinfo, simply remove `\d` from the regex......updated the answer....please check. – Mamun Dec 26 '18 at 14:11
@mamum its not allowed plain string , Ex: console.log (validateStr("sdsdsdsdsdsd"));// I should return true , but in ur case it returns false – parithi info Dec 27 '18 at 13:02
@parithiinfo, you can use `/[a-zA-Z]+([(@!#\$%\^\&*\)\(+=._-]{1,})?/` with quantifier `?`......but in that case `validateStr("sdsdsdsd45678")` will also be true...... – Mamun Dec 27 '18 at 13:19
If i use this , console.log(validateStr("sdsdsdsd45678")); this one is also come as true . – parithi info Dec 27 '18 at 14:10
Let us [continue this discussion in chat](https://chat.stackoverflow.com/rooms/185836/discussion-between-parithi-info-and-mamun). – parithi info Dec 27 '18 at 14:19

Majedur · Answer 2 · 2018-12-27T03:45:14.257

0

You can use this code to track number and special characters in your string value.

 function checkNumberOrSpecialCharacters(stringValue){

    if( /[^a-zA-Z\-\/]/.test( stringValue) ) {
        alert('Input is not alphabetic');
        return false;
    }
 alert('Input is alphabetic');
    return true;     
}

edited Dec 27 '18 at 03:45

answered Dec 26 '18 at 12:04

Majedur

3,074
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How to check the string has number and special characters in JavaScript?

2 Answers2