Function call does not execute its definition

Question

I seek advice on a matter relating to this function.

I have tried various editing and indentation on the code, but it is showing the same result.

It shows NameError: name 'sentence' is not defined although I have defined it in the function.

The code is:

def about (name, age, likes):
  sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
  return sentence

about ("Jack", 23, "programming")
print (sentence)

score 3 · Accepted Answer · answered Dec 26 '18 at 11:54

3

You should call function and assign it to an variable:

def about(name, age, likes):
    sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
    return sentence

Then

val = about("Jack", 23, "programming")
print(val)

you can also use sentence instead of val but this will not be the same sentence in function scope.

answered Dec 26 '18 at 11:54

Mehrdad Pedramfar

10,941
4
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1

Thank you man! It works! Thank you @mehrdad-pedramfar – Mafruh Faruqi Dec 26 '18 at 15:14

score 1 · Answer 2 · answered Dec 26 '18 at 12:14

1

try this now....

def about (name, age, likes):
    sentence = "Meet {}, he is {} years old and likes {}".format(name,age,likes)
    return sentence

print(about('rohit',23,'programming'))

sentense scope is bounded to about function... and trying to print it out of the function scope may not work.

answered Dec 26 '18 at 12:14

Karthikeyan K

229
2
7

It also works bro! A BIG thanks for the help – Mafruh Faruqi Dec 26 '18 at 15:16

Function call does not execute its definition

2 Answers2