split element inside list python

Question

I was trying to split the element inside the list based on certain length, here is the list ['Mar 18 Mar 17 Mar 16 Mar 15 Mar 14']. Could any one help me to retrieve the values from the list in the following format:

['Mar 18','Mar 17','Mar 16','Mar 15','Mar 14']

i have gone through the link and this doesnt solve my problem. The link explains about splitting a string in to two and set as constant, where as in my question the number of values may vary every time. schwobaseggl answer helped me to solve the issue. Thanks — Jagan S, Dec 28 '18 at 07:44

score 1 · Accepted Answer · answered Dec 28 '18 at 07:05

1

A regular expression based approach that would handle cases like Apr 1 or Dec 31 as well as multiple elements in the initial list:

import re

lst = ['Mar 18 Mar 17 Mar 16 Mar 15 Mar 14']

[x for y in lst for x in re.findall(r'[A-Z][a-z]+ \d{1,2}', y)]
# ['Mar 18', 'Mar 17', 'Mar 16', 'Mar 15', 'Mar 14']

answered Dec 28 '18 at 07:05

user2390182

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Exactly right approach (Y) – Anoop Kumar Dec 28 '18 at 07:22

score 0 · Answer 2 · answered Dec 28 '18 at 07:04

0

list = ['Mar 18 Mar 17 Mar 16 Mar 15 Mar 14']

span = 2
s = list[0].split(" ")
s = [" ".join(words[i:i+span]) for i in range(0, len(s), span)]
print(s)

For me, this prints

['Mar 18','Mar 17','Mar 16','Mar 15','Mar 14']

Taken from this answer.

answered Dec 28 '18 at 07:04

rLevv

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In this case It need manipulation. this will not provide desired result – Anoop Kumar Dec 28 '18 at 07:23

score 0 · Answer 3 · answered Dec 28 '18 at 07:27

0

Try this code !

You can do it by the concept of regular expression (just by import re library in python)

import re

lst = ['Mar 18 Mar 17 Mar 16 Mar 15 Mar 14 Mar 2']

obj = re.findall(r'[A-Z][a-z]+[ ](?:\d{2}|\d{1})', lst[0])

print(obj)

Output :

['Mar 18', 'Mar 17', 'Mar 16', 'Mar 15', 'Mar 14', 'Mar 2']

answered Dec 28 '18 at 07:27

Usman

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15
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`(?:\d{2}|\d{1})` can be simplified to either `\d{1,2}` or `\d\d?` – user2390182 Dec 28 '18 at 07:45
yes , we can simply with `\d{1,2}` but not with `\d\d` because date might be 1 digit integer or two digit integer in the range of 1 to 31 days – Usman Dec 28 '18 at 07:47
Hence the `?` to mark the second digit optional ;) – user2390182 Dec 28 '18 at 07:49
yes. we can do the second digit optional like `\d\d?`. Thanks alot :) – Usman Dec 28 '18 at 07:50
That's what I was suggesting all along in my first comment :) – user2390182 Dec 28 '18 at 07:51

score 0 · Answer 4 · answered Dec 28 '18 at 07:29

0

You can also try this one

>>> list = ['Mar 18 Mar 17 Mar 16 Mar 15 Mar 14']
>>> result = list[0].split(" ")
>>> [i+' '+j for i,j in zip(result[::2], result[1::2])]

Output

['Mar 18', 'Mar 17', 'Mar 16', 'Mar 15', 'Mar 14']

answered Dec 28 '18 at 07:29

Anoop Kumar

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split element inside list python

4 Answers4