Laravel - Array to string conversion

Question

I am trying to show the related applications to abstract, I have used the code below but I am getting this error

Array to string conversion

My controller

public function show($A_ID){

  $abstract = Project::find($A_ID);

  // I believe the issue is caused by the line below but I am not sure what is wrong about it 

  $applications = Application::find($A_ID);
  return view('Abstracts.show')->with('abstract', $abstract)
                             ->with($applications);
}

EDIT: (add model v1.0 and v1.1)

My model (v1.0) which show the error of Array to string conversion

<?php

namespace App;
use Illuminate\Database\Eloquent\Model;
use Traits\HasCompositePrimaryKey; 

class Application extends Model{


    //Table name
    protected $table = 'student_application';

    //composite key
    protected $primaryKey = array('A_ID', 'S_ID');
    protected $fillable = ['S_Justification' ];
    public $incrementing = false;}

My edited Model (V1.1)

    <?php
    namespace App;

    use Illuminate\Database\Eloquent\Model;
    use App\Traits\HasCompositePrimaryKey; 

    class Application extends Model{
    use HasCompositePrimaryKey; 


    //Table name
    protected $table = 'student_application';

    //composite key
    protected $primaryKey = array('A_ID', 'S_ID');
    protected $fillable = ['S_Justification' ];
    public $incrementing = false;}

I want to note that the composite key is declared using this answer number two with currently 59 votes

For more information here is my view

@if (count($applications)>0)
@foreach ($applications as $application)
<tr>
        <td><h5>{{$application->S_ID}}</h5></td>
</tr>
@endforeach
@else 
<p> This project has no applications </p>
@endif

yes I have already included it, also I have updated to model code you can see it now with include trait — ALI ISMAEEL, Dec 29 '18 at 05:26
there is a `find` method he is using, have you included it too? — Ahmed Nour Jamal El-Din, Dec 29 '18 at 05:29
hmm `use Traits\HasCompositePrimaryKey;` should be in your model, not above it! please make sure of it — Ahmed Nour Jamal El-Din, Dec 29 '18 at 05:33
As far as i know, find() returns only 1 row. so in your blade file you dont need to use @foreach, since it has only 1 row. — MONSTEEEER, Dec 29 '18 at 05:34
@AhmedNourJamalEl-Din I tried your solution to move the use Traits but now it this error 'shows Trait 'App\Traits\HasCompositePrimaryKey' not found' — ALI ISMAEEL, Dec 29 '18 at 05:37
where is your trait located? is it in your app directory? if not please add `use` statement above the class, and use it in your model like `use HasCompositePrimaryKey;` — Ahmed Nour Jamal El-Din, Dec 29 '18 at 05:40
it is in `app\Traits\HasCompositePrimaryKey; ` do I have to move it or anything? — ALI ISMAEEL, Dec 29 '18 at 05:44
@AhmedNourJamalEl-Din Note: I have not edited anything in the traits file, I have copied and pasted it — ALI ISMAEEL, Dec 29 '18 at 05:47
Just fix your `use` and `namespace` statements of the trait and you are good to go. — Ahmed Nour Jamal El-Din, Dec 29 '18 at 06:09
@AhmedNourJamalEl-Din I have changed my model to `use HasCompositePrimaryKey; ` and my namespace in trait `namespace App; ` and still same error — ALI ISMAEEL, Dec 29 '18 at 06:25
if your trait is located in `app\traits` then trait namespace must be in `App\Traits`, and use it in your model like `use Traits\HasCompositePrimaryKey;`. I hope it helps. if not please provide your project structure about traits — Ahmed Nour Jamal El-Din, Dec 29 '18 at 07:20
my app folder http://prntscr.com/m0x7ad , my Traits folder http://prntscr.com/m0x7hk , I useed the `namespace App\Traits` and the `use Traits\HasCompositePrimaryKey;` — ALI ISMAEEL, Dec 29 '18 at 08:43
depending on images, try the following: `namespace App\Traits;` for your trait and in model add `use App\Traits\HasCompositePrimaryKey;` in top of the file and under the class definition add `use HasCompositePrimaryKey;` — Ahmed Nour Jamal El-Din, Dec 29 '18 at 09:24
@AhmedNourJamalEl-Din Please check model v1.0 and model v1.1 which is the current code — ALI ISMAEEL, Dec 29 '18 at 09:37
@AhmedNourJamalEl-Din Now I used your last suggestion and the error changed I believed the issue almost solve, my new error is related to the view which is `Undefined variable: applications` , Update: I have checked to return dd($applications) it returns null, am I finding it right ? — ALI ISMAEEL, Dec 29 '18 at 09:41
why did you make new class?? you have one, just add `use HasCompositePrimaryKey; ` to it! — Ahmed Nour Jamal El-Din, Dec 29 '18 at 09:43
`$applications = Application::find($A_ID);` this return null while there are some applications for that certain $A_ID — ALI ISMAEEL, Dec 29 '18 at 09:51
well, I think `Array to string conversion` is solved, as I see $A_ID is just a part of your primary key, you have to provide full key. — Ahmed Nour Jamal El-Din, Dec 29 '18 at 09:53
recheck the link in your question for composite key, it may help you — Ahmed Nour Jamal El-Din, Dec 29 '18 at 09:55
I would thank you very much for all your help @AhmedNourJamalEl-Din — ALI ISMAEEL, Dec 29 '18 at 10:07
@AhmedNourJamalEl-Din Now its works yeah, my current issue that this will show only for id of 201400858 `['A_ID' => $A_ID , 'S_ID' => '201400858' ]` I am searching how to say find all not just for 201400858 — ALI ISMAEEL, Dec 29 '18 at 10:34
you may change the provided `find` method so it accepts `LIKE` instead of `=` and it may work with wildcard `*` — Ahmed Nour Jamal El-Din, Dec 29 '18 at 10:36
yea, and exactly this line `$query->where($key, '=', $id[$i]);` so it accepts `$operator` as parameter and pass it like this `$query->where($key, $operator, $id[$i]);` — Ahmed Nour Jamal El-Din, Dec 29 '18 at 10:51
I don't think I need to use that , I have just replaced `find` with `where` and added `->get()` — ALI ISMAEEL, Dec 29 '18 at 12:40

Ali Özen · Answer 1 · 2018-12-29T06:46:25.157

0

You are passing string to view.

return view('Abstracts.show')->with(['abstract'=> $abstract)];

give it a try.

Edit: Or you can use like that.

with(array('order' => function($query)

Anyway you need to pass array in here. If you are just want to use ->with('abstract'); you need to add abstract function. For example:

public function deliveries() {
       // this might be $this->hasOne... depends on what you need
     return $this->hasMany('Abstracts', 'conditions', 'id')->where('foo', '!=', 'bar');
    }

edited Dec 29 '18 at 06:46

answered Dec 29 '18 at 06:41

Ali Özen

1,525
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there is no issue with my return view with abstracts, the issue with applications – ALI ISMAEEL Dec 29 '18 at 08:37
You can do samethings to the applications. Just give it a try. you can import applications in function($query) that works for sure. – Ali Özen Dec 29 '18 at 08:43
can you clarify this line a little bit more `with(array('order' => function($query) ` I am not where and how to use it – ALI ISMAEEL Dec 29 '18 at 08:49

Mahbub · Answer 2 · 2018-12-29T10:19:58.140

0

$applications is an object in your controller but you are accesing $applications as collection in your view file. You may try this:

$applications = Application::where('id', $A_ID)->get();

return view('Abstracts.show', compact('abstract', 'applications'));

edited Dec 29 '18 at 10:19

answered Dec 29 '18 at 08:41

Mahbub

4,812
1
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Unfortunately, doesn't work. I believe my issue in this line `$applications = Application::find($A_ID);` – ALI ISMAEEL Dec 29 '18 at 08:48
`$applications = Application::where('id', $A_ID)->get()` – Mahbub Dec 29 '18 at 09:56

Laravel - Array to string conversion

2 Answers2