I need to modify this code, to replace the number 1 with the number of the current measure. So, the first number in each measure will always rise.
instead of
1
2
3
4
1
2
3
4
1
2
3
4
(with each number on its own line), I'd now print
1 2 3 4 2 2 3 4 3 2 3 4
, and so on.
beats_per_measure = 4
measures = 5
for measure in range(0, measures):
for beat in range(1, beats_per_measure + 1):
print(beat)
Perhaps you need something like below.
beats_per_measure = 4
measures = 5
### loop from 1 to 5 measures ###
# remove +1 to get sequence of 4
# iterations
for measure in range(1, measures+1):
# print the measure value in a single line
# first at iteration of outer loop to get
# the sequence
print(measure, end = " ")
## then loop from 2 to measure
for beat in range(2, beats_per_measure + 1):
# print each beat
print(beat, end = " ")
Output
1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4
You can solve this by manually printing the measure you are currently in - followed by the remaining beats:
beats_per_measure = 4
measures = 5
for m in range(measures):
# manually print the measure you are in
print(m+1, end=" ") # do not put a newline after the print statement
# print the beats 0...bmp-1 == 0,1,2 - output adds 2 to each => 2,3,4
for beat in range(beats_per_measure - 1):
print(beat+2, end = " ") # do not put a newline after the print statement
Output:
1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4
* * * * *
The * are manually printed, the others filled in by the for-loop
You can read more about printing in one line here:
Doku: https://docs.python.org/3/library/functions.html#print
You can also create a generator that counts measures on its own (I'll mark the measure-number with * manually):
def gimme_measure(beats_per_measure):
beats = list(range(2,beats_per_measure+1))
yield gimme_measure.measure
gimme_measure.measure += 1
yield from beats
gimme_measure.measure = 1 # defines the starting measure
# print 2*10 measures
for _ in range(10):
print(*gimme_measure(4), end = " ") # the * decomposes the values from the generator
for _ in range(10): # continues the beat measuring
print(*gimme_measure(4), end = " ") # the * decomposes the values from the generator
Output:
1 2 3 4 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4 6 2 3 4 7 2 3 4 8 2 3 4 9 2 3 4 10 2 3 4 11 2 3 4 12 2 3 4 13 2 3 4 14 2 3 4 15 2 3 4 16 2 3 4 17 2 3 4 18 2 3 4 19 2 3 4 20 2 3 4
* * * * * * * * * ** ** ** ** ** ** ** ** ** ** **
The generator gimme_measure has it's own measure counter which is initialized to 1 and incremented each time you generate a new measure using the generator - if you do not reset the gimme_measure.measure to some other number it keeps counting upwards any time you print another generated measure.
You can even chain different bpm together:
# piece with 2 measures of 4 beats, 2 measures of 8 beats, 2 measures of 3 beats
for _ in range(2):
print(*gimme_measure(4), end = " ")
for _ in range(2): # continues the beat measuring
print(*gimme_measure(8), end = " ")
for _ in range(2): # continues the beat measuring
print(*gimme_measure(3), end = " ")
Output:
1 2 3 4 2 2 3 4 3 2 3 4 5 6 7 8 4 2 3 4 5 6 7 8 5 2 3 6 2 3
* * * * * *
If you are using python 3, this is the answer(tested):
beats_per_measure = 4
measures = 5
for measure in range(1, measures+1):
print(measure, end = ' ')
for beat in range(2, beats_per_measure + 1):
print(beat, end = ' ')
Or if you are using python 2, use this (tested):
beats_per_measure = 4
measures = 5
for measure in range(1, measures+1):
print measure,
for beat in range(1, beats_per_measure + 1):
print beat,
More info here: https://www.quora.com/How-do-I-print-something-on-the-same-line-in-Python
