Search specific value in array and return value

Question

$meal_type= "Free Breakfast|Free Wireless";
if ($meal_type != '' && $meal_type !='None') {
    $meal = explode('|', $meal_type);

    $meal = array_search('Breakfast',$meal);

    $meal = $meal_type;
} else {
    $meal= 'No Breakfast';
}
echo $meal;

This is my code. here i want to search Breakfast in the array and return searched value, if not found return No Breakfast.

Here i was explode string to array with | symbol and returned array search Breakfast if exist return funded array value else echo No Breakfast value.

i tried this but not working `array_search('Breakfast',$meal_type);` — Niranjan, Jan 02 '19 at 07:19
Update your question with your actual code and what you have tried. It will save everyone a lot of time. You may also have a small typo or spelling mistake. — Second2None, Jan 02 '19 at 07:21
Possible duplicate of [Search for PHP array element containing string](https://stackoverflow.com/questions/12315536/search-for-php-array-element-containing-string) — Muhammad Bilal, Jan 02 '19 at 07:44

Alive to die - Anant · Accepted Answer · 2019-01-02T08:28:09.483

3

A simple foreach() will do the job:-

<?php
$match_counter =0;
$array = Array
(
    0 => 'Free Breakfast',
    1 => 'Free Wireless Internet'
);
$search = 'Breakfast';

foreach($array as $arr){
    if(stripos($arr,$search) !==false){
        echo $arr.PHP_EOL;
        $match_counter++;
    }
}
if($match_counter ==0){
    echo 'No '.$search;
}

Output:-

https://3v4l.org/ogOEB (occurrence found)

https://3v4l.org/AOuTJ (occurrence not found)

https://3v4l.org/NTH1W (occurrence found more than one time)

Reference:- stripos()

edited Jan 02 '19 at 08:28

answered Jan 02 '19 at 07:28

Alive to die - Anant

70,531
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thankx for reminding the (occurrence found more than one time) cases – sradha Jan 02 '19 at 08:39
1

Glad to help you – Alive to die - Anant Jan 02 '19 at 14:03

sradha · Answer 2 · 2019-01-02T08:38:24.520

2

<?php
$array = array('Free Breakfast','Free Wireless Internet');

$string = 'Breakfast';
foreach ($array as $a) {


    if (stripos($a, $string) !== FALSE) {  
        echo  $string; 
        return true;
    }
}
echo "No" .$string;
return false;

?>

You can also use stripos() for case-insensitive.

case 1 : if array contains multiple same values

<?php
$array = array('Free Breakfast','Free Wireless Internet' ,'breakfast time');

$string = 'Breakfast';
$flag=true;
foreach ($array as $key=> $a) {

    if (stripos($a, $string) !== FALSE) {  
        $flag = false;

        echo  $string." contain in key position ".$key.'<br>'; 
        //return true;
    }
}
if($flag)
{
echo "No" .$string;
}



?>

edited Jan 02 '19 at 08:38

answered Jan 02 '19 at 07:33

sradha

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Your answer correct for current scenario, but it will not cover all occurrences, if presented more than one time inside the array:-https://3v4l.org/ND0IF – Alive to die - Anant Jan 02 '19 at 08:26
@AlivetoDie I added some code for other cases, I think it will be helpful in other cases. – sradha Jan 02 '19 at 08:36

Search specific value in array and return value

2 Answers2