Opening a socket to see output with bash

Question

Is it possible to open a socket on a given URL and get its output printed, something similar to curl but for TCP using bash?

Currently I am using a Google Chrome browser extension -> Simple Websocket Client but i would like to make my own scripts and direct the output in my preferred files etc..

Can it be done ?

PS: so far I have also used telnet but I need to pass a path too host:port:path.

Errr... `curl`? I feel like `curl` is the answer. Why it is not working for you? — Poshi, Jan 02 '19 at 21:35
Does [this](https://stackoverflow.com/questions/47860689/how-to-read-websocket-response-in-bash) question help you? — Denis Zavedeev, Jan 03 '19 at 11:41

score 1 · Accepted Answer · answered Jan 03 '19 at 02:16

If you version of bash supports networking

#!/bin/bash
set -u
host="$1"
port="$2"
path="$3"
exec 3<>/dev/tcp/$host/$port
printf '%s\r\n' "$path" >&3
cat <&3

if you are hitting a HTTP server the probably you have to pass the GET requests as path, something like

script example.com 80 $'GET / HTTP/1.1\r\nConnection: close\r\n'

Opening a socket to see output with bash

1 Answers1