I am trying to create an arbitrary time using batch files. I am trying to subtract set values (such as 1 day, 1 month, and 2000 years) from my code to display the system time subtracted by the set values stated previously. For the hours and minutes, I am subtracting 10 hours and 10 minutes (shown in code as different values). I am also aware that date and time are variables related to my system. ~ Please ignore
Important - My problem now is with this part:
if %minb% EQU 60 set /a minb=%minb%-60 & set /a hourb=%hourb%+1
if %hourb% EQU 24 set /a hourb=%hourb%-24 & set /a dayb=%dayb%+1
if %dayb% EQU 30 set /a dayb=%dayb%-30 & set /a monthb=%monthb%+1
if %monthb% EQU 12 set /a monthb=%monthb%-12 & set /a yearb=%yearb%+1
I can't seem to be able to make the minutes reset to 0 and have the hours add 1 when the minute value hits 60, and same with the hour-day, day-month, month-year relationships, other than that, the problems with my code are mostly fixed. When I run the code and wait for the minutes (or add to the time difference) to reach 60, they just pass 60 and don't reset nor add to the hoursb value.
.
My date and time formats are:
- Short date: M/d/yyyy
- Long date: dddd, MMMM d, yyyy
- Short time: h:mm
- Long time: h:mm:ss
I am using Windows 10.
Please note that the values in the set /a do not match my description, but of course they can be changed around. They are set to the shown numbers for test purposes only.
EDIT:
Code:
@echo off
:start
set day=%date:~-7,2%
set month=%date:~-10,2%
set year=%date:~-4,4%
set hour=%time:~0,2%
set min=%time:~3,2%
set /a "hourb=%hour%-10"
set /a "minb=%min%+30"
set /a "dayb=%day%-1"
set /a "monthb=%month%-1"
set /a "yearb=%year%-2000"
if %minb% lss 10 set minb=0%minb%
if %hourb% lss 10 set hourb=0%hourb%
if %dayb% lss 10 set dayb=0%dayb%
if %monthb% lss 10 set monthb=0%monthb%
if %minb% EQU 60 set /a minb=%minb%-60 & set /a hourb=%hourb%+1
if %hourb% EQU 24 set /a hourb=%hourb%-24 & set /a dayb=%dayb%+1
if %dayb% EQU 30 set /a dayb=%dayb%-30 & set /a monthb=%monthb%+1
if %monthb% EQU 12 set /a monthb=%monthb%-12 & set /a yearb=%yearb%+1
cls
:: ———————————————————————–
@mode con cols=20 lines=6
title Arbitrary Clock
:time
echo.
echo. %hourb%:%minb%
echo.
echo. %dayb%-%monthb%-%yearb%
echo.
ping -n 2 0.0.0.0 >nul
cls
goto :start
Alright, so as you can see in the new edit to the code, I set the values to the stated at the beginning of this question. Subtracting 10 from the hours, subtracting 1 from the days and months, and subtracting 2000 from the years. I added 30 to the minutes to show the problem right now.
So my system time is 4:40, 1/5/2019. Alright?
The displayed time on the clock is 06:70, 04-00-19.
The desired outcome is 07:10, 04-12-18.
This was edited heavily. Thanks in advance.