I have the following code:
fn example(known_primes: &[i32], number: i32, prime: i32, limit: i32) {
let mut is_prime = true;
for prime in known_primes {
if number % prime == 0 {
is_prime = false;
break;
}
if *prime > limit {
break;
}
}
}
Why do I need to dereference prime
in the second condition (*prime > limit
), when I don't need to do so in the first one (number % prime == 0
)?
Both %
and <
are operators that take two numbers and return something. The only difference seems to be in what they return (a number vs. a boolean). While Why isn't it possible to compare a borrowed integer to a literal integer? does explain what would be required to make the code work (implementations for all overloads, ideally in the standard library), it does not say why it does work for a % b
. Is there a fundamental difference between these operators? Or is it just not implemented yet?