Hook jQuery methods on JavaScript selected elements

Question

Easier to explain with simple code:

$("#element").fadeOut(); // jQuery; works as expected

I want to use .fadeOut() and select element with JS like this:

document.getElementById("element").fadeOut(); // Does not work

How do I make this work and is there any point of doing this (performance wise)?

Any thought is appreciated. Thanks.

jQuery methods expect a jQuery Object in order to work. E.g. `$()` See more info about them here https://stackoverflow.com/questions/6445180/what-is-a-jquery-object — ProEvilz, Jan 09 '19 at 03:01

score 1 · Answer 1 · answered Jan 09 '19 at 02:59

1

You can wrap the element in $():

$(document.getElementById("element")).fadeOut();

However, you may find it's easier just to use the jQuery ID selector #:

$('#element').fadeOut();

answered Jan 09 '19 at 02:59

Obsidian Age

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score 1 · Accepted Answer · answered Jan 09 '19 at 02:59

You can assign the fadeOut property name to HTMLElement.prototype, and call jQuery's fadeOut from inside it:

// $("#element").fadeOut(); // jQuery; works as expected

HTMLElement.prototype.fadeOut = function(...args) {
  $(this).fadeOut(...args);
}

document.getElementById('element').fadeOut();

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="element">text</div>

That said, overwriting built-in objects like HTMLElement is pretty bad practice and can cause problems - it would be better to just do what you were doing originally, and call .fadeOut on a jQuery object containing the desired element(s).

score 0 · Answer 3 · answered Jan 09 '19 at 03:01

0

If you want to use JQuery features, you need to use $() to call the method i.e. fadeout(). See JQuery Selector.

Now that if you want to do it in vanilla JavaScript then check this out.

answered Jan 09 '19 at 03:01

holydragon

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Hook jQuery methods on JavaScript selected elements

3 Answers3