How to get specific number of digits? Python

Question

How would I format my float digits so that there is always 7 digits no matter the direction?

The value could be any of the following but I always want 7 like below

The portion I have right now is

return "%.7f" % fd

How can I adjust that to get my desired output? or maybe link me to something similar I could try and read from..>?

Yea exactly, hence the dependability on the program you're coding. — J_Zoio, Jan 09 '19 at 22:02
But you are asking for a number to always have 7 digits? Unless I read that wrong... — J_Zoio, Jan 09 '19 at 22:04

score 6 · Accepted Answer · answered Jan 09 '19 at 22:06

6

Try if this can work for you:

n = 123.456789
decimals = 7 - len(str(int(n)))
print('{:.{prec}f}'.format(n, prec=decimals))
#=> 123.4568

The drawback is that it rounds up.

answered Jan 09 '19 at 22:06

iGian

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That's okay if it rounds up. Thank you! – tejosa Jan 09 '19 at 22:11

J_Zoio · Answer 2 · 2019-01-09T22:10:10.167

1

It depends on the context of the program, in my opinion... If you just want the numbers to the right to be 6 decimals, use:

"{:.6f}".format(whatevervar)

In other contexts maybe convert it to a string and use len() to evaluate the number of digits.

Hope this helps!

EDIT: Seeing your comments, I would recommend using a conditional to define what you are trying to do. When the number has no decimals (check this thread for how to do it: How to check if a float value is a whole number ) leave it as it is, when it has decimals, round it up with the code I posted above.

edited Jan 09 '19 at 22:10

answered Jan 09 '19 at 22:01

J_Zoio

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Thanks, I'll check it out! – tejosa Jan 09 '19 at 22:18

How to get specific number of digits? Python

2 Answers2