Truth value of an array is ambiguous

Asked Jan 10 '19 at 14:38

Active Jan 10 '19 at 14:53

Viewed 84 times

I have a list of tuples A containing an array and a boolean value, and a sub list of it, B. I'm trying to remove the sublists' elements from the main list, so im using:

    v1 = np.array([1, 2, 3])
    v2 = np.array([1, 2, 2])
    A = [(v1, True), (v2, False)]
    B = [(v1, True)]
    new_list = [x for x in A if x not in B]

I'm getting the following error:

The truth value of an array with more than one element is ambiguous. Use a.any() or a.all().

What truth values? And how will any() help here? i'm looking for tuples not booleans

edited Jan 10 '19 at 14:53

asked Jan 10 '19 at 14:38

CodeHoarder

5

can you post more code what is A and B – Kunal Mukherjee Jan 10 '19 at 14:40
1

You have to share the list so that we can reproduce your problem – yatu Jan 10 '19 at 14:42
2

What is v1 and v2? – Kunal Mukherjee Jan 10 '19 at 14:44
Based on my intuition, I'm pretty sure you want to use `(x not in B).any()`, but there's better ways to do it. – Mad Physicist Jan 10 '19 at 14:45
The code you've written doesn't produce the effect you've described. Please give us a full, runnable code segment that produces that error. – Silvio Mayolo Jan 10 '19 at 14:46
`if x not in B` is a boolean expression. The `if` accepts only one True/False value. The `x not in B` produces an array of True/False values. Hence the ambiguity error. – hpaulj Jan 10 '19 at 17:46
@MadPhysicist it still gives the same error – CodeHoarder Jan 11 '19 at 08:26

Truth value of an array is ambiguous

0 Answers0