Relative path using File.separator

Question

I had hard coded path in my code. Now, I have to use File.separator (or any other class) so the my path will work on Windows or Linux machine.

Why my new code isn't working? Help me overcome the issue.

This is my old code (that works on Windows):

readFile("./Use-cases/"+duplicatedExcelText);

And this is my new code that causes exception and errors:

readFile(File.separator+"."+File.separator+ "Use-cases"+File.separator +
 duplicatedExcelText);

Your old code starts the file path with a '.', your new code does not. — nicomp, Jan 15 '19 at 10:35
you wrote old code starts like "./Use-cases/" and new code starts like "File.separator + . +" which is "/." just reverse it — Oğuzhan Aygün, Jan 15 '19 at 10:37
Whenever you build a string be prepared to print it out, or use the debugger and step in to readFile to see what the built string looks like. — Gem Taylor, Jan 15 '19 at 11:24

score 1 · Accepted Answer · answered Jan 15 '19 at 11:40

1

This solved my problem:

readFile("."+ File.separatorChar + "Use-cases" + 

File.separatorChar + duplicatedExcelText);

answered Jan 15 '19 at 11:40

Tal Angel

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score 0 · Answer 2 · answered Jan 15 '19 at 10:36

The problem is that you construct a string that goes:

'\' + "." ...

in the end.

Windows doesn't like that for relative paths!

And according to this, you can use / for all OSes. Using File.separator is only recommended when you want to display the final path to human users (to avoid confusing them).

Relative path using File.separator

2 Answers2