SOAP xml in return - Android

Question

I'm using k2SOAP for Android when dealing with webservices.

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("ProjectID", 1);

SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
soapEnvelope.dotNet = true;
soapEnvelope.setOutputSoapObject(request);

HttpTransportSE httpTransport = new HttpTransportSE(URL);

try {

    httpTransport.call(SOAP_ACTION, soapEnvelope);
    SoapObject result = (SoapObject) soapEnvelope.getResponse();
    String resultString = result.toString();
}

I know there is nothing wrong with the code since it works with the w3 web service. But w3c returns a string as an answer this web service returns an XML. The answer I get back looks like this when I show it in log:

anyType{schema=anyType{element=anyType{complexType=anyType{choice=anyType{element=an    yType{complexType=anyType{sequence=anyType{element=anyType{}; 
element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; element=anyType{}; }; }; }; }; }; 
unique=anyType{selector=anyType{}; field=anyType{}; }; }; }; diffgram=anyType{}; }

Which basically is a lot of noise and I'm not sure on how to get the information from this or how I should parse it or. My ultimate goal is to put the information I get in to a local database but since I don't know how to get the information from the String I don't know put the info in the database.

So what I want to do is to somehow parse the information and put it in a local database which I already built the classes for. How do I get the data from the SoapObject result? There is a slight possibility the web service info is empty, but my question is still the same.

Hi Joakim, Have you find any way for parsing this type of response...if so,please provide some help... is it possible to use any native parser of android ? — Nandagopal T, Jun 30 '11 at 12:04

score 4 · Accepted Answer · answered Oct 10 '11 at 10:34

4

Two Things you need to change

1)Add this "httpTransport.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>");"

line above "httpTransport.call(SOAP_ACTION, soapEnvelope);"

2) String resultString = result.toString();

Replace the above line with following one

String resultString=httpTransport.responseDump;

This will return response as xml formated String

answered Oct 10 '11 at 10:34

surya

477
1
7
19

This solution did not work for me. I had the same problem. Information is coming like above but not with xml format. Any additional help ? – Hasanur Sep 18 '12 at 10:14
You're probably using "SoapObject results=(SoapObject) envelope.bodyIn;" to get the file. Use HttpTransportSE ht = getHttpTransportSE(); ht.responseDump; and the file should come out in XML format. – Gene Jul 02 '14 at 22:12

score 2 · Answer 2 · answered Sep 19 '12 at 10:05

The provided answer did not work for me rather lines bellow worked for me. Try the following lines, hope this will give you data with XML tags,

httpTransport.debug=true; 
httpTransport.call(SOAP_ACTION, soapEnvelope);
String ss=httpTransport.responseDump; 
Log.d("Result --- ", ss);

This will print the complete xml file which has been returned by the web service.

score 0 · Answer 3 · answered Dec 15 '11 at 06:17

0

Try it this WAy .

try {

    httpTransport.call(SOAP_ACTION, soapEnvelope);
    SoapObject result = (SoapObject) soapEnvelope.getResponse();


String element = ((SoapObject)result.getPropertySafely("schema")).getPropertySafely("element").toString();

answered Dec 15 '11 at 06:17

Imran Khan Niazi

137
1
6

SOAP xml in return - Android

3 Answers3

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