Creating instance of a class dynamically

Question

I am trying to create and use an instance of a class dynamically but keep running into the error " a is a variable but used as a type".

  //First we need to find the project that holds all of our entity models in the assembly
        var assembly = AppDomain.CurrentDomain.GetAssemblies()
                      .Where(x => x.FullName.Contains("MyProject.Models"))
                      .FirstOrDefault();

 //Now we need to search through the assembly to match the Entity to the supplied TableName
        var type = assembly.GetTypes()
                  .FirstOrDefault(t => t.Name == localTableName);

        var a = Activator.CreateInstance(type);

Why can't I use this like so

List<a> dynamicList = new List<a>;

or what I need to do this

var query = context.Database.SqlQuery<a>(...);

In that duplicate that you have linked it just translates a list. I may not need a list I may need the class to use in a SQLQuery

Im not great in C# but.. it should be more like.. " = new List" — Ess Kay, Jan 16 '19 at 14:41
If "a" is a type than do not name variable "a". Change `var a ...` to `var b ...` and it should be ok. It seems that you have name duplication variable vs class. — Pablo notPicasso, Jan 16 '19 at 14:42
`a` is not a `Type`. It is an instance of that type. You will need to follow the duplicate and use `type` as the generic parameter. — , Jan 16 '19 at 14:43
@PablonotPicasso No pablo a is not the type it just a variable name. The type is a instance of my Class named "MYCLASS" a is a variable that represents that class — Terrance Jackson, Jan 16 '19 at 14:54
@TerranceJackson No, `type` is a variable containing the runtime type information for your class. `a` contains an instance of that class. — , Jan 16 '19 at 16:09
@Amy so why am I unable to use that class in the context of var query = context.Database.SqlQuery(...) — Terrance Jackson, Jan 16 '19 at 16:21
@TerranceJackson Because you can't use *runtime* type information at *compile* time. Also, `SqlQuery` won't work for another reason, because, again, `a` is not a variable containing runtime type information. `type` is that variable. `a` is an instance of your class. — , Jan 16 '19 at 16:49

Creating instance of a class dynamically

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