Can we declare size of array is zero?

Question

main()
{
    int x[0];
    scanf("%s",x);
   printf("%s",x);
}

Why this program not show any error when I input qwerty79 and this program give me output qwerty79?

The code declares an array with a “zero size”. Then accesses it in an manner of Undefined Behavior - this is a classical buffer overflow that “didn’t crash the program” (when compiled with a particular compiler and run with a particular runtime). It’s either luck or a curse.. — user2864740, Jan 20 '19 at 05:59

score -3 · Answer 1 · answered Jan 20 '19 at 06:23

-3

In this you declare array of int x with 0 members means their no memory space allocated for an array and their is no memory location name x.So , their is no type checking when you are entered string in integer and one another reason is that compiler only know that there is some variable x but that type is not known because their is no memory allocation of x.So,your program not given any error.For detail info you must read compilation process state theory which is a part of the Compiler Design Subject.

answered Jan 20 '19 at 06:23

Kushal Master

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This answer is completely wrong. A C-program containing an array of size zero is ill-formed and the compiler is required to issue a diagnostic in that case. – Swordfish Jan 20 '19 at 08:26
diagnostic process is mentioned in compiler design book – Kushal Master May 27 '19 at 10:53

Can we declare size of array is zero?

1 Answers1