Problem with subprocess.call, not working as intended

Asked Jan 23 '19 at 13:28

Active Jan 23 '19 at 13:28

Viewed 61 times

The same command string works fine on terminal(macOS) but not inside Python script

youtube-dl -f "bestvideo[height<=480]+bestaudio" "video link" -o "download folder" --referer "referer url"

works fine on terminal

but on python script it outputs the error:

subprocess.call(f'''youtube-dl -f "bestvideo[height<={video_resolution}]+bestaudio" "{(url)}" -o "{path}/{id}.mp4" --referer "{(url)}"''', timeout=900)

FileNotFoundError: [Errno 2] No such file or directory:

asked Jan 23 '19 at 13:28

ggnoredo

well, you do need a comma between parameters – Ulug Toprak Jan 23 '19 at 13:39
but it's working on windows? @UlugToprak – ggnoredo Jan 23 '19 at 13:45
Just for completeness try to add `shell=True` – Ulug Toprak Jan 23 '19 at 14:25
That did the trick, thank you @UlugToprak – ggnoredo Jan 23 '19 at 15:02
There is however security concerns about this. You should check this [Answer](https://stackoverflow.com/a/36008455/6139043) – Ulug Toprak Jan 23 '19 at 15:05

Problem with subprocess.call, not working as intended

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