How to create array from 1 to n digit with single line of code in ruby

Question

Need to create an array of 1 to n numbers with a single line of code in ruby.

I have tried it using while loop. But I'm sure there are other simpler way of doing this in ruby.

a = []
b = 1
while b < 100 do
  a << b
  b += 1 
end

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]

The exact question (even "1 to 10") was asked [here](https://stackoverflow.com/questions/11173173/create-array-of-n-items-based-on-integer-value). — Cary Swoveland, Jan 23 '19 at 18:08

score 12 · Accepted Answer · answered Jan 23 '19 at 16:56

12

Convert a range into an array.

(1..n).to_a

answered Jan 23 '19 at 16:56

Ursus

29,643
3
33
50

score 0 · Answer 2 · answered Jan 23 '19 at 17:15

0

another way You can just splat a range:

[*1..n]

example

[*1..10]
=>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Or

a= Array(0..10)
puts a # => =>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

answered Jan 23 '19 at 17:15

Giridharan

568
4
14

Downvote. Stolen from https://stackoverflow.com/a/11173335/131160 – jcsahnwaldt Reinstate Monica Dec 14 '20 at 00:53

How to create array from 1 to n digit with single line of code in ruby

2 Answers2

Or