Swift Encoding Technique for Custom nested Objects?

Question

I am need to get encoding for the nested object

class person {
var name: String?
var phone: String?
var address: Address?
}

class Address {
var area: String?
var city: String?
}

I tried

let data = try? JSONEncoder().encode(person)
let json = try? JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String: Any]

but Address key value pair is not getting.

Would you like to update your question by including the missing code related to `Person` and `Address` classes? — Kamran, Jan 24 '19 at 09:11
To encode the classes with `JSONEncoder` you have to adopt `Codable`. — vadian, Jan 24 '19 at 09:13

score 3 · Accepted Answer · answered Jan 24 '19 at 09:18

Just implement Encodable

class Person: Encodable {
  var name: String?
  var phone: String?
  var address: Address?
}

class Address: Encodable {
  var area: String?
  var city: String?
}
let address = Address()
address.area = "Area"
address.city = "City"
let person = Person()
person.name = "name"
person.address = address

let encoded = try JSONEncoder().encode(person)

Robert Dresler · Answer 2 · 2019-01-24T09:51:18.527

1

struct Person: Encodable {
    var name, phone: String
    var address: Address
}

struct Address: Encodable {
    var area, city: String
}

conform your models which you need to encode to protocol Encodable
types should start with big capital letter
if you're sure that properites won't be nil don't make them optional
you can make your models structs instead of classes

Then just encode your object

let data = try? JSONEncoder().encode(person)

When you need print your encoded data, you need to convert them to String

let data = try! JSONEncoder().encode(person)
let json = String(data: data, encoding: .utf8) ?? ""

if you need to encode object with key "person" and person object as value, encode dictionary

let data = try! JSONEncoder().encode(["person": person])
let json = String(data: data, encoding: .utf8) ?? ""

edited Jan 24 '19 at 09:51

answered Jan 24 '19 at 09:14

Robert Dresler

10,580
2
22
40

Thanks Robert but the I need json { "person": { "name": "name",phone : "phone number" , "address": { "area" : "area", "city": "city name" } }} – satish reddy Jan 24 '19 at 09:19
1

`Person` should be `Encodable` too. – user28434'mstep Jan 24 '19 at 09:22
@satishreddy, then do `encoder.encode(["person": person])`, where `person` is instance of `Person` type, and `encoder` is `JSONEncoder`. – user28434'mstep Jan 24 '19 at 09:26
@RobertDresler, because OP asks to encode **whole** `Person` in the comment just above. With all the fields. – user28434'mstep Jan 24 '19 at 09:35
1

@user28434 yes, in comment yes. But from question it wasn't clear – Robert Dresler Jan 24 '19 at 09:36

Swift Encoding Technique for Custom nested Objects?

2 Answers2