java substring of string with OR option

Question

Let say I have a list of strings like:

List myList = new ArrayList();
myList.add("person [something]");
myList.add("person 'something'");

so in my strings sometimes I have [ and sometimes '

and now I would like to get substrings but I don't know how to do this if I would like to cut my string in one of the two chars. Can anyone tell me whether that option is possible? I tried something like:

List finalOne = new ArrayList();
for(String ss: myList){
finalOne.add(ss.substring("[" || "'" ))

}

I expect to get all substrings starting from char "[" or starting from "'" in one run

use something like `indexOf` to find out which char is present or use a regex to split correctly. — luk2302, Jan 26 '19 at 20:12
`substring` doesn't work this way (https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#substring(int)) — Denis Sablukov, Jan 26 '19 at 20:46

uneq95 · Accepted Answer · 2019-01-26T20:33:58.670

3

You can use (?<=\[)(.*?)(?=\]) and (?<=\')(.*?)(?=\') regular expressions to find the string between square brackets and single quotes.

You can take a look at this, for searching pattern in java, and this, for the regular expression.

edited Jan 26 '19 at 20:33

answered Jan 26 '19 at 20:28

uneq95

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I need further help :( I did something like that in java String regex = "(?<=\\[)(.*?)(?=\\])"; String string = "sdsds [test] fdfddf"; Pattern pattern = Pattern.compile(regex); Matcher matcher = matcher.pattern(string) log.info(matcher.group(0)); but I get NO MATCHERS Have I done something wrong? – EdXX Jan 26 '19 at 21:50
You might wanna post another question – uneq95 Jan 26 '19 at 21:52

java substring of string with OR option

1 Answers1