Check diffrence Number is Less than 10 or Geater Than 10 in python

Question

How to find if a number is less than or greater than 10 for difference.

Example1: If a is 100 and b is 91. This is almost Matching.

Example2: If a is 100 and b is 89. This is not at all Matching.

Below is the code and its working fine. Is there any other easiest or best way to achieve

a = 110
b = 100
c = a - b
d = a - 10
if a > b:
    if (a - b) <= 10:
        print "This is almost Matching"
    else:
        print "This is not at Matching"
else:
    if (b - a) <= 10:
        print "This is almost Matching"
    else:
        print "This is not at Matching"

Expected and actual are getting same

You can change your condition to if `abs(a -b) <= 10`, so no need to verify if `a > b` — Dani Mesejo, Jan 29 '19 at 12:57
See this: https://stackoverflow.com/questions/13602170/how-do-i-find-the-difference-between-two-values-without-knowing-which-is-larger — Dani Mesejo, Jan 29 '19 at 13:03

DirtyBit · Accepted Answer · 2019-01-29T13:06:01.087

2

You need to look for the absolute value of the difference (a,b):

The method abs() returns absolute value of x - the (positive) distance between x and zero.

a = 100
b = 110
print(abs(a - b))  # 10

if abs(a -b) <= 10:
    print("This is almost Matching")
else:
    print("This is not at Matching")

OUTPUT:

10
This is almost Matching

edited Jan 29 '19 at 13:06

answered Jan 29 '19 at 13:00

DirtyBit

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score 1 · Answer 2 · answered Jan 29 '19 at 12:59

1

Use abs to find the absolute difference:

a = 110
b = 100
c = abs(a-b)
if c<=10:
    print ("This is almost Matching")
else:
    print ("This is not at Matching")

answered Jan 29 '19 at 12:59

ѕняєє ѕιиgнι

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Check diffrence Number is Less than 10 or Geater Than 10 in python

2 Answers2