don't correct out put in C#

Question

example I enter 1357 and program out 106 instead of 10

        string num = Console.ReadLine();
        Console.Write(Convert.ToInt32(num[1]) + Convert.ToInt32(num[3]));
        Console.ReadKey();

why would it do that? use a debugger to check the runtime values of the string, the chars, and the conversion results. hint: `Console.WriteLine(Convert.ToInt32(num[1]));` is 51, the ascii codepoint of 3 — Cee McSharpface, Jan 30 '19 at 21:12
You're adding the integer values of the backing characters for "3" and "7" which are 51 and 55, respectively. You want to add the parsed values of those characters. — Jonathon Chase, Jan 30 '19 at 21:13

score 2 · Accepted Answer · answered Jan 30 '19 at 21:13

2

First convert the single characters to a string before converting to integer. Convert will use the Unicode code point value when converting char to integer directly.

var value = Convert.ToInt32(num[1].ToString()) + Convert.ToInt32(num[3].ToString());

answered Jan 30 '19 at 21:13

NineBerry

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Good explanation of what is going on. – Rich Jan 30 '19 at 22:07

don't correct out put in C#

1 Answers1