Apply array.sort() default algorithm to string properties of objects in an array

Question

From Array.prototype.sort() documentation:

The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.

What if target array's elements are objects and we want apply above algorithm to targetKey's value?

const targetArray = [
    { targetKey: 'March' },
    { targetKey: 'Jan' },
    { targetKey: 'Feb' },
    { targetKey: 'Dec' }
]

Expected result:

[
    { targetKey: 'Dec' },
    { targetKey: 'Feb' },
    { targetKey: 'Jan' },
    { targetKey: 'March' }
]

Some simple solutions?

Warning: We don't considering the ordering by alphabet in this question. We need to order due sequences of UTF-16 code units values.

Have you tried something or just looking for someone to write it for you? — Kosh, Feb 01 '19 at 05:00
@KoshVery, No. Currently, I need to know, are some simple solutions exists or no. If no - I'll find the complicated solution. — Takeshi Tokugawa YD, Feb 01 '19 at 05:02
Possible duplicate of [Sort array of objects by string property value](https://stackoverflow.com/questions/1129216/sort-array-of-objects-by-string-property-value) and [How to sort object array based on key in typescript](https://stackoverflow.com/questions/39850339) and [Sort Array of Objects by specific key value](https://stackoverflow.com/questions/43816557) and [Sort Array of object by object field](https://stackoverflow.com/questions/51194830) — adiga, Feb 01 '19 at 07:20

Shidersz · Accepted Answer · 2019-02-01T05:09:46.467

You can use the compareFunction function with String::localeCompare() on the target keys:

const targetArray = [
    { targetKey: 'March' },
    { targetKey: 'Jan' },
    { targetKey: 'Feb' },
    { targetKey: 'Dec' }
];

targetArray.sort((a, b) => a.targetKey.localeCompare(b.targetKey));

console.log(targetArray)

And if you don't want to mutate (modify) the original array, you can clone it with slice() and then sort the cloned one.

const targetArray = [
    { targetKey: 'March' },
    { targetKey: 'Jan' },
    { targetKey: 'Feb' },
    { targetKey: 'Dec' }
];

let res = targetArray.slice(0).sort((a, b) => a.targetKey.localeCompare(b.targetKey));

console.log(targetArray)
console.log(res);

score 2 · Answer 2 · answered Feb 01 '19 at 05:03

You can also use destructing assingment to get the targetKey and then use .localeCompare to compare both values:

const targetArray = [
    { targetKey: 'March' },
    { targetKey: 'Jan' },
    { targetKey: 'Feb' },
    { targetKey: 'Dec' }
],

res = targetArray.sort(({targetKey:a}, {targetKey:b}) => a.localeCompare(b));
console.log(res);

score 0 · Answer 3 · answered Feb 01 '19 at 05:14

You can use Intl.collator

const targetArray = [
    { targetKey: 'March' },
    { targetKey: 'Jan' },
    { targetKey: 'Feb' },
    { targetKey: 'Dec' }
];

let op = targetArray.sort(({targetKey:a},{targetKey:b})=>new Intl.Collator('en').compare(a,b));

console.log(op)

Apply array.sort() default algorithm to string properties of objects in an array

3 Answers3