Java Optional: flatmap and orElseGet

Question

I've coded that:

Optional.ofNullable(this.cache.get(id))
    .orElseGet(this.referenceService.get(id));

The problem is that this.referenceService.get returns an Optional.

So, I'm getting this compilation message:

The method orElseGet(Supplier<? extends Reference>) in the type Optional<Reference> is not applicable for the arguments (Optional<Reference>)

Any ideas?

I think you have to call `.orElseGet(() -> this.referenceService.get(id))`. — Amongalen, Feb 01 '19 at 13:03

score 3 · Answer 1 · answered Feb 01 '19 at 13:03

3

Starting with java 9 you can use Optional.or()

Optional<String> foo = Optional.empty();
Optional<String> bar = Optional.ofNullable("Bar");
System.out.println(foo.or(() -> bar));

answered Feb 01 '19 at 13:03

baao

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score 1 · Answer 2 · answered Feb 01 '19 at 13:04

If you're using Java 9, you have access to Optional.or, which accepts a Supplier<Optional<T>>.

If not, the below pattern works:

Optional.ofNullable(this.cache.get(id))
    .orElseGet(() -> this.referenceService.get(id)
        .orElseThrow(()-> new RuntimeException("Expected service to return something")));

Java Optional: flatmap and orElseGet

2 Answers2