compare single dimensional Array with Multidimensional array in javascript

Question

I am using javascript to compare a single array and a multidimensional array. Here i want to compare those 2 array and the matched value should be shown.

arr[1,2,3] value to be searched in multidimensional array " md2 ".

This is my Code :: i have taken an single array and other as multidimensional array

var arr = [1,2,3];
var md2 = [[23,8,2],[1,5,8],[1,2,3],[8,5,2]];
for(var j=0; j<md2.length ; j++){
  if(arr == md2[j]){
    console.log(arr + " ... " + md2[j]);
  }
}

Required O/P :- [1,2,3] should match and should be displayed in the console

Possible duplicate of [How to compare arrays in JavaScript?](https://stackoverflow.com/questions/7837456/how-to-compare-arrays-in-javascript) — Khauri, Feb 03 '19 at 16:35

score 0 · Answer 1 · answered Feb 03 '19 at 16:35

0

You can use .find() and .every() methods to find array inside multi-dimensional array:

var arr1 = [1,2,3];
var arr2 = [1,2,5];
var md2 = [[23,8,2],[1,5,8],[1,2,3],[8,5,2]];

var searchAndPrint = (a1, a2) => {
  let arr = a1.find(a => a.every((v, i) => v === a2[i]));
  
  if(arr)
    console.log(arr);
  else
    console.log("No Results");
};

searchAndPrint(md2, arr1);
searchAndPrint(md2, arr2);

answered Feb 03 '19 at 16:35

Mohammad Usman

37,952
20
92
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A shorter solution (but maybe less performant), could be to coerce arrays in string and then compare them, in place of using `every` – Christian Vincenzo Traina Feb 03 '19 at 16:36

score 0 · Answer 2 · answered Feb 03 '19 at 16:35

You can't compare arrays in js. If you wanna compare simple arrays you can convert them to string to compare. This method is not applicable to array containing objects.

var arr = [1,2,3];
var md2 = [[23,8,2],[1,5,8],[1,2,3],[8,5,2]];
for(var j=0; j<md2.length ; j++){
  if(arr.toString() === md2[j].toString()){
    console.log(arr + " ... " + md2[j]);
  }
}

score 0 · Answer 3 · answered Feb 03 '19 at 16:36

0

You can use JSON.stringify to compare the arrays.

var arr = [1,2,3];
var md2 = [[23,8,2],[1,5,8],[1,2,3],[8,5,2]];
for(var j=0; j<md2.length ; j++){
  if(JSON.stringify(arr) === JSON.stringify(md2[j])){
    console.log(arr + " ... " + md2[j]);
  }
}

answered Feb 03 '19 at 16:36

Fullstack Guy

16,368
3
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score 0 · Answer 4 · answered Feb 03 '19 at 16:37

For checking, you need to check the length and the items directly, because you have no same object reference.

var arr = [1, 2, 3],
    md2 = [[23, 8, 2], [1, 5, 8], [1, 2, 3], [8, 5, 2]];
    
console.log(md2.some(a => arr.length === a.length && a.every((v, i) => v === arr[i])));

compare single dimensional Array with Multidimensional array in javascript

4 Answers4