Dynamic path symfony

Question

I have this code:

href="{{ path('new') }}"

Now is necessary use one variable in this section:

href="{{ path(item.ruta) }}"

But this show a error:

An exception has been thrown during the rendering of a template ("Unable to generate a URL for the named route "" as such route does not exist.").

How can solution this problem?

It seems that `item.ruta` is empty, so no route could be generated. You could specifiy a fallback like this `{{ path(item.ruta ? item.ruta : 'new') }}` — Fabian Schmick, Feb 04 '19 at 15:07
Thanks Fabian. Now show this error with this code: "An exception has been thrown during the rendering of a template ("Unable to generate a URL for the named route "#" as such route does not exist.")." — juanitourquiza, Feb 04 '19 at 15:10
It is not a solution, the item.ruta is inside a loop. The idea is to assign the content of item.ruta within path — juanitourquiza, Feb 04 '19 at 15:20
What do you mean with `The idea is to assign the content of item.route within path` ? — Fabian Schmick, Feb 04 '19 at 15:21

score 4 · Accepted Answer · answered Feb 04 '19 at 15:17

It seems that item.ruta is empty, so no route could be generated.

You could specifiy a fallback like this {{ path(item.ruta ? item.ruta : 'new') }} or if you want to stay on the current page you need to do something like descripted here: get current url in twig template?

{% if item.ruta %}
    href="{{ path(item.ruta) }}"
{% else %}
    href="{{ path(app.request.attributes.get('_route'), app.request.attributes.get('_route_params')) }}"
{% endif %}

or if you really want # only, then remove the path function call

{% if item.ruta %}
    href="{{ path(item.ruta) }}"
{% else %}
    href="#"
{% endif %}

Dynamic path symfony

1 Answers1