create variable size array

Question

I would like to create an numpy array like the one below, except I want to be able to create a variable shape array. So for the one below it would be n=3. Is there an a slick way to do this with numpy, or do I need a for loop.

output data:

import numpy as np

np.array([1,0,0],[0,1,0],[0,0,1],[1,1,1],[0,0,0])

you want to create array with random numbers using given shape? — Sociopath, Feb 05 '19 at 06:38
You are making us guess - what size? what pattern? just what do you mean by 'variable'? — hpaulj, Feb 05 '19 at 07:16

score 0 · Answer 1 · edited Feb 05 '19 at 08:05

0

Say you want to create array with name d having row number of rows and col number of columns. It would also initialize all elements of the array with 0.

d = [[0 for x in range(col)] for y in range(row)]

You can access any element I,j by d[i][j].

edited Feb 05 '19 at 08:05

taurus05

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answered Feb 05 '19 at 06:40

Neha

1

The OP hasn't mentioned that there are `row` number of rows and `col` number of columns. – taurus05 Feb 05 '19 at 06:43
sorry I don't think I worded this very well but I also think I found the answer in another post https://stackoverflow.com/questions/14931769/how-to-get-all-combination-of-n-binary-value – modLmakur Feb 06 '19 at 05:06

create variable size array

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