How to put a return statement in lambda python with expression?

Question

I'm planning to simplify my code without defining the function. Is it possible?

a = lambda x:1 if x>1 return x-1 else return x

output 0 = 0, 1=1 ,2=1 ,3=2

[PEP8](https://www.python.org/dev/peps/pep-0008/#programming-recommendations): "Always use a def statement instead of an assignment statement that binds a lambda expression directly to an identifier." — jpp, Feb 07 '19 at 08:51

score 2 · Answer 1 · answered Feb 07 '19 at 07:15

2

a = lambda x:1 if x>1 return x-1 else return x

This is syntactically wrong. If you want to use if else, inline to make it work like a ternary operator in other languages. You will have to write:

# expression1 if condition else expression2
x-1 if x>1 else x

So it becomes:

a = lambda x: x-1 if x>1 else x

Remember lambda in python can only have a single line of code.

answered Feb 07 '19 at 07:15

himank

taurus05 · Accepted Answer · 2019-02-07T06:55:21.583

1

This is syntactically correct way to use lambdas in Python

>>> a = lambda x: x-1 if x>1 else x
>>> a(3)
2
>>> a(1)
1
>>> a(0)
0
>>> a(2)
1

For better understanding about lambdas visit this link

edited Feb 07 '19 at 06:55

answered Feb 07 '19 at 06:41

taurus05

2 Answers2