undefined variable in PHP function

Asked Feb 07 '19 at 14:19

Active Feb 07 '19 at 14:24

Viewed 47 times

I used a ins function to insert in data base and i create a object for mysqli.The mysqli object shows error of undefined variable.and my code was

<?php
include "config.php";
global $mysqli;
 $mysqli = &new mysqli($host, $db_user, $db_pass, $db);
function ins($name)
{
 $stmt=$mysqli->prepare("insert into table demo values(?)");
 $stmt->bind_param("s",$name);
 $stmt->execute();
 $stmt->close();
}
ins("krishna");
?>

Here the server name ,user name password and db name are stored in config.php

asked Feb 07 '19 at 14:19

krishna

if you can echo these variables in that file, just above the line this means they are in the scope – Marcin Feb 07 '19 at 14:21
you should add the exact, full error message with the line number where it occurs – yunzen Feb 07 '19 at 14:21
1

You need to define the global $mysqli inside your function. – aynber Feb 07 '19 at 14:24

undefined variable in PHP function

0 Answers0