Need to get substring from string in bash

Question

I'm trying to get Atom version in bash. Thid regex is working, but I need a substring from string, which giving grep. How can I get version from this string?

<span class="version">1.34.0</span>

curl https://atom.io/ | grep 'class="version"' | grep '[0-9]\+.[0-9]\+.[0-9]\+'

Possible duplicate of [Extract substring in Bash](https://stackoverflow.com/questions/428109/extract-substring-in-bash) — Arc676, Feb 08 '19 at 21:14
Note if you have Gnu grep you can use the -P option for perl-style regex's and the -o option to print only what matches the pattern. Try this as your last command in the pipeline:`grep -oP "\d+\.\d+\.\d+"` Oh and notice escaping the dot for a literal dot, otherwise it means any character. — Gary_W, Feb 08 '19 at 22:14

score 2 · Accepted Answer · answered Feb 08 '19 at 21:47

2

with awk

$ curl ... | awk -F'[<>]' '/class="version"/{print $3; exit}'

answered Feb 08 '19 at 21:47

karakfa

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score 0 · Answer 2 · answered Feb 08 '19 at 21:20

You can achieve this by using the cut command and adding your respective delimiters; in your case this would be the > and < tags encapsulating the version.

Input:

curl -s https://atom.io/ \
| grep 'class="version"' \
| grep '[0-9]\+.[0-9]\+.[0-9]\+' \
| cut -d '>' -f2 \
| cut -d '<' -f1

Output:

1.34.0

*added the curl -s flag to make output silent, personal choice

Need to get substring from string in bash

2 Answers2