regex to match 2 different words in a string

Question

I've went through so many posts about this but can't find one that works. I have object keys that I want to search through and see if they have either of two specific words in them and filter them if the exist.

Example:

const obj = {
   time_pop: 'fhfvla',
   icon: 'dsfval',
   home_pops: 'valffg',
   title: 'sdfsdfs',
   pop: 'sfsdfsd',
   rattle: 'sdfdsf',
   pops: 'sfsdfsdf'
}

I want a regex that can find either the word pop || pops in object keys. I'm currently looping through and have the key and am using this as my regex

  const expr = /\b(pop|pops)\b/;

  const only = Object.entries(obj).filter(([k, v]) => {
    return expr.test(k);
  })

The above only works for one word not if it has a _ in it. For example this is not working. time_pop home_pops

They are return false when they should return true because the word pop or pops is in them.

Get rid of word boundaries if you want it to match partially — Pushpesh Kumar Rajwanshi, Feb 09 '19 at 05:19

score 0 · Accepted Answer · answered Feb 09 '19 at 05:21

0

You can use /pops?/ if you want to match partially.

const obj = {time_pop: 'fhfvla',icon: 'dsfval',home_pops: 'valffg',title: 'sdfsdfs',pop: 'sfsdfsd',rattle: 'sdfdsf',pops: 'sfsdfsdf'}

const only = Object.entries(obj).filter(([k, v]) => {
    return /pops?/g.test(k)
})


console.log(only)

answered Feb 09 '19 at 05:21

Code Maniac

37,143
5
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Ah thats smart. Just incase I change the name how would I do it if I had two different keys I wanted to look for. for example. pop or popper – me-me Feb 09 '19 at 05:30
`pop(per)?` this will be enough. you can do this when you have one as substring of another one. else just add `|` between them – Code Maniac Feb 09 '19 at 05:31
Weird when I put it into my code it didn't work. But when I remove the g from the end it works. Why would that be ? – me-me Feb 09 '19 at 05:50
@me-me what didn't work ? g is global flag which means match all the occurrences https://stackoverflow.com/questions/12993629/what-is-the-meaning-of-the-g-flag-in-regular-expressions – Code Maniac Feb 09 '19 at 05:55
@me-me if you re use regex with test it will produce problem so you can drop the g flag or you can use like i did – Code Maniac Feb 09 '19 at 05:59
Its returning false when it should be return true. When I remove the g it works. const expr = /pops?/; works but when I use const expr = /themes?/g; it does not – me-me Feb 09 '19 at 06:00
yes I was using it with test. Do you happen to know why it causes a problem with test ? – me-me Feb 09 '19 at 06:01
1

@me-me you can read this post https://stackoverflow.com/questions/1520800/why-does-a-regexp-with-global-flag-give-wrong-results# – Code Maniac Feb 09 '19 at 06:05

score 0 · Answer 2 · answered Feb 09 '19 at 05:27

Here, there were also errors (syntax) in your code.

const obj = {
  time_pop: 'fhfvla',
  icon: 'dsfval',
  home_pops: 'valffg',
  title: 'sdfsdfs',
  pop: 'sfsdfsd',
  rattle: 'sdfdsf',
  pops: 'sfsdfsdf'
};

const expr = /pop|pops/;

const only = Object.entries(obj).filter(([k, v]) => expr.test(k));

console.log(only);

score 0 · Answer 3 · answered Feb 09 '19 at 05:34

0

In a regular expression, the metacharacter \b represents a word boundary. Essentially, it will only match if there is a non-word character before (pop|pops). An underscore, however, is a word character. Try:

const expr = /(\b|_)(pop|pops)\b/

answered Feb 09 '19 at 05:34

Steven Kaufman

59
1
5

regex to match 2 different words in a string

3 Answers3