How to multiply the numbers in a list by themselfs

Question

I am answering the Euler project questions in python and I don't know how to multiply a list by itself I can get a list within the range though

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Dupe: https://stackoverflow.com/questions/10271484/how-to-perform-element-wise-multiplication-of-two-lists-in-python — Patrick Artner, Feb 13 '19 at 16:46

score -1 · Answer 1 · edited Jul 23 '19 at 12:37

-1

Try this:

myList = [0,1,2,3,4,5,6,7,8,9]
newList = []

for item in myList:
    newList.append(pow(item,2))

print (newList)

Returns:

[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]

edited Jul 23 '19 at 12:37

ncica

answered Feb 13 '19 at 16:51

C. Lang

score -1 · Answer 2 · edited Feb 13 '19 at 17:16

-1

you can use the map function:

list_1 = [1, 2, 3, 4, 5]
list_2 = list(map(lambda x: x**2, list_1))

Output

[1, 4, 9, 16, 25]

edited Feb 13 '19 at 17:16

ShadowRanger

answered Feb 13 '19 at 16:57

Barbara

1

General note: If you need a `lambda` to use `map`, don't use `map`. Just use an equivalent list comprehension or generator expression. `map` is only a win when you have an existing, C implemented mapper function; if the function doesn't meet those criteria `map` is slower. This should really just be `list_2 = [x ** 2 for x in list_1]` or `list_2 = [x * x for x in list_1]`, both of which are shorter, simpler, and faster than `map`+`lambda`. – ShadowRanger Feb 13 '19 at 17:17

2 Answers2