Javascript: Regex case insensitive

Question

I have the following regex expression being used in a JavaScript function.

regex = /(([a-zA-Z]{3})+([0-9]{12})+(.zip))$/g;

I want the last characters (.zip) also as case insensitive. How to achieve this ? Thanks

`/(([a-z]{3})+([0-9]{12})+(\.zip))$/gi` – Gurmanjot Singh Feb 15 '19 at 06:07 — Gurmanjot Singh, Feb 15 '19 at 06:07

ellipsis · Answer 1 · 2019-02-15T06:17:10.463

2

Use i modifier

var regex = /(([a-z]{3})+([0-9]{12})+(\.zip))$/ig; 
var str="abAc772345678989.ZIP";
console.log(regex.test(str))

edited Feb 15 '19 at 06:17

answered Feb 15 '19 at 06:08

ellipsis

1

Why not use the `i` flag simply? Also, the `.` before the `zip` in the regex will match any character except newline. Not just `.` – Gurmanjot Singh Feb 15 '19 at 06:10
1

OP says "case-insensitive" so to be thorough, you'd need to handle "ZiP", "zIP", "ZIp", etc – Phil Feb 15 '19 at 06:10

1 Answers1