Splitting a string on non digits

Question

I am trying to split a string on any char that is not a digit.

orig = '0 1,2.3-4:5;6d7'
results = orig.split(r'\D+')

I expect to get a list of integers in results

0, 1, 2, 3, 4, 5, 6, 7

but instead I am getting a list with a single string element which matches the original string.

Possible duplicate of [Python split string based on regex](https://stackoverflow.com/questions/13209288/python-split-string-based-on-regex) — Tim Biegeleisen, Feb 17 '19 at 13:59

score 9 · Accepted Answer · answered Feb 17 '19 at 13:59

9

Well ... you are using str.split() - which takes characters to split at - not regex. Your code would split on any '\D+' - string inside your text:

orig = 'Some\\D+text\\D+tosplit'
results = orig.split(r'\D+')  # ['Some', 'text', 'tosplit']

You can use re.split() instead:

import re

orig = '0 1,2.3-4:5;6d7'
results = re.split(r'\D+',orig)
print(results)

to get

['0', '1', '2', '3', '4', '5', '6', '7']

Use data = list(map(int,results)) to convert to int.

answered Feb 17 '19 at 13:59

Patrick Artner

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If you want to get non-digit and digit sections, you can add group to regex: `re.split(r'(\D+)', orig)` – rysson Jul 15 '20 at 13:26

score 1 · Answer 2 · answered Feb 17 '19 at 14:04

1

Try this:

orig = '0 1,2.3-4:5;6d7'
[i for i in orig if i.isdigit()]

answered Feb 17 '19 at 14:04

Mehrdad Pedramfar

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nice one - although if you have numbers with more then one digit (`'12 142, 92'`) you will get `[1,2,1,4,2,9,2]` instead of `[12,142,92]` – Patrick Artner Feb 17 '19 at 14:09
@PatrickArtner Yes, I noticed that. but maybe it works for OP – Mehrdad Pedramfar Feb 17 '19 at 14:10

score 0 · Answer 3 · edited Feb 17 '19 at 15:17

0

for i in '0 1,2.3-4:5;6d7':
    try:
        print(int(i),end=' ')
    except:
        continue

0 1 2 3 4 5 6 7

edited Feb 17 '19 at 15:17

Moshe Slavin

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answered Feb 17 '19 at 14:57

Suhail Riyaz

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That is not "splitting" a list. You are just printing the numbers. – Valentino Feb 17 '19 at 15:32
create a list, l=[], then in try/catch block '' l.append(int(i)) '' instead print(int(i)). – Suhail Riyaz Feb 17 '19 at 16:10

Splitting a string on non digits

3 Answers3

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