How to multiply dictionary keys?

Question

I would like to multiply the keys of this dictionary by 2

d = {2: (1,2), 8: (2,4), 30: (10,3)}

for i in d.keys():
    print(i*2)

4
16
60

But d is still {2: (1,2), 8: (2,4), 30: (10,3)}

How can I get d to become {4: (1,2), 16: (2,4), 60: (10,3)} ?

This does not make any sense. Do you want the key to multiply with each value or just the first one? — DirtyBit, Feb 18 '19 at 07:58
see if the answer posted below helped? if it did, you may accept it by clicking on the tick sign beside it. cheers! — DirtyBit, Feb 18 '19 at 15:18

score 0 · Answer 1 · answered Feb 18 '19 at 07:59

0

Can you try the following:

d = {2: (1,2), 8: (2,4), 30: (10,3)}
d = {k**2: v for k, v in d.items()}

answered Feb 18 '19 at 07:59

Jeril

score 0 · Answer 2 · answered Feb 18 '19 at 08:01

0

dictionary comprehension:

double = {k*2:v for (k,v) in d.items()}

answered Feb 18 '19 at 08:01

bollence

score 0 · Accepted Answer · answered Feb 18 '19 at 08:04

0

I believe you want is:

Multiply each key with 2. Not the square of it.

d = {2: (1,2), 8: (2,4), 30: (10,3)}
d = {k*2: v for (k, v) in d.items()}
print(d)

OUTPUT:

{4: (1, 2), 16: (2, 4), 60: (10, 3)}

answered Feb 18 '19 at 08:04

DirtyBit

score 0 · Answer 4 · answered Feb 18 '19 at 08:05

0

new_d = {}
for k,v in d.items():
    new_d[k*2] = v
d = new_d

answered Feb 18 '19 at 08:05

Rashid Mahmood

score 0 · Answer 5 · answered Feb 18 '19 at 08:07

0

Try this:

d = dict((key*2, value) for (key, value) in d.items())

answered Feb 18 '19 at 08:07

Mehrdad Pedramfar

5 Answers5