How can I reverse the order of this structure?

Question

How can I reverse the order of these items?

L = []
items = [4,3],[1,2]
L.append(items)
## reverse the order of items in L such that L contains : [([1,2],[4,3])]

Reverse the order of items in L such that L contains : [([1,2],[4,3])]

Have a look at [slice notation](https://stackoverflow.com/questions/509211/understanding-slice-notation) in python, `items[::-1]` — yatu, Feb 19 '19 at 11:29

score 3 · Answer 1 · answered Feb 19 '19 at 11:31

3

You can flip each tuple by:

L = [(b, a) for a, b in L]

answered Feb 19 '19 at 11:31

Dan D.

Mykola Zotko · Answer 2 · 2019-02-19T14:40:07.297

2

You can use the function reversed() to reverse the order of elements in the array:

L = []
items = [4,3],[1,2]
L.append(items)

L = [tuple(reversed(i)) for i in L]
# [([1, 2], [4, 3])]

Alternatively you can use:

L = [(i[1], i[0]) for i in L]

or

L = [(L[0][1], L[0][0])]

edited Feb 19 '19 at 14:40

answered Feb 19 '19 at 11:48

Mykola Zotko

Rafael Laurindo · Accepted Answer · 2019-02-19T12:22:49.557

1

You can do the following:

items = [4,3],[1,2]
L = items[::-1]
print(L) # output[([1,2], [4,3])]

edited Feb 19 '19 at 12:22

answered Feb 19 '19 at 11:34

Rafael Laurindo

Your solution prints `([1, 2], [4, 3])` and not a list of tuples. – Mykola Zotko Feb 19 '19 at 12:26

3 Answers3