How can I get the part of the string which is inside the characters like brackets i.e. "(" " )"?

Question

Below are three strings. Each string has some characters inside the brackets. I want to save those characters which are inside the brackets in some other variables. Can somebody suggest the possible ways to do this?

String name_and_code1 = "MountainBlues(MB)"; 
String name_and_code2 = "Rock(RoRo)Roll";
String name_and_code3 = "(TFT)TitForTat";

Possible duplicate of [Pattern to extract text between parenthesis](https://stackoverflow.com/questions/24256478/pattern-to-extract-text-between-parenthesis) — Arnaud, Feb 19 '19 at 13:51

score 2 · Accepted Answer · answered Feb 19 '19 at 13:50

You can make use of indexOf(). First, find the indices of '(' and ')' and then use substring(). Something like:

int start = myString.indexOf('(');
int end = myString.indexOf(')');
String result = myString.substring(start+1, end); 
//start+1 because we don't want the '('

score 2 · Answer 2 · answered Feb 19 '19 at 13:52

2

Using a regular expression:

String a = "MountainBlues(MB)";
Matcher matcher = Pattern.compile("\\((.+)\\)").matcher(a);
matcher.find();
System.out.println(matcher.group(1));

prints MB

answered Feb 19 '19 at 13:52

f1sh

11,489
3
25
51

For optimization the `Pattern` could be saved inside a `static` variable – Lino Feb 19 '19 at 13:54
Correct, but not appropriate at the level at OP's experience. – f1sh Feb 19 '19 at 13:56

score 1 · Answer 3 · answered Feb 19 '19 at 13:50

1

String insideBrackets(String input){
    String result = "";
    boolean bracket = false;
    for(int i = 0: i < input.length(); i++){
        if(!bracket && input.charAt(i) == '('){
            bracket = true;
        }
        if(bracket && input.charAt(i) == ')'){
            bracket = false;
        }
        if(bracket){
            result += input.charAt(i);
        }
    }
    return result;
}

i think this should work. if it doesnt tell me right away

answered Feb 19 '19 at 13:50

Alan

949
8
26

Maybe use a `StringBuilder` as string concatenation in loops will produce a lot of garbage intermediate objects – Lino Feb 19 '19 at 13:51
maybe. but this smells like homework and i dont think they even touched stringbuilder yet. idk – Alan Feb 19 '19 at 13:53
1

Well if you already provide their homework, you should do it the correct way in the first place, but this way they learn probably nothing and just copy paste it. *shrug* – Lino Feb 19 '19 at 13:55
well that sure as hell is =true. – Alan Feb 19 '19 at 13:57

score 0 · Answer 4 · answered Feb 19 '19 at 13:52

0

You can use regular expression for this:

Pattern p = Pattern.compile(".*(\\(.*\\)).*");
Matcher m = p.matcher("mytext(with)parentheses");

if(m.matches()) {
    String inner = m.group(1); // now inner contains "(with)" (without quotes)
    //...
}

answered Feb 19 '19 at 13:52

spi

1,673
13
19

How can I get the part of the string which is inside the characters like brackets i.e. "(" " )"?

4 Answers4