BeautifulSoup find class contains some specific words

Question

I have searched around to find about how to find a class with name contains some word but I don't find it. I want to take the information from class named with word footer on it.

<div class="footerinfo"> <span class="footerinfo__header"> </span> </div>

<div class="footer">
    <div class="w-container container-footer">
    </div>
</div>

I have tried this but it still don't work

soup.find_all('div',class_='^footer^'):

and

 soup.find_all('div',class_='footer*'):

Does anyone have any idea on doing this?

Please check https://stackoverflow.com/questions/34660417/beautiful-soup-if-class-contains-or-regex — Kamal, Feb 21 '19 at 09:10
you provided a wrong footer indicator, '^footer^, this is not the same as "footer" so it doesnt find it — Julian Silvestri, Feb 21 '19 at 14:06

score 5 · Accepted Answer · answered Feb 21 '19 at 09:11

You can use CSS selectors which allow you to select elements based on the content of particular attributes. This includes the selector *= for contains.

for ele in soup.select('div[class*="footer"]'):
    print (ele)

or regex

import re

regex = re.compile('.*footer.*')
soup.find_all("div", {"class" : regex})

BeautifulSoup find class contains some specific words

1 Answers1