PHP : how to retrieve piped stuff

Question

Not a dupe, in this very case I am trying to run my php thru a command line and it does not work as expected (php uses php://input and I do not want to modify them)

I am trying the following:

echo 'hello' | php -r 'print("input content:".file_get_contents("php://input"));'

I am expecting something like

content:hello

to be printed out , but get only

content:

Possible duplicate of [What is the meaning of php://input & php://output and when it needs to use?](https://stackoverflow.com/questions/7186189/what-is-the-meaning-of-php-input-php-output-and-when-it-needs-to-use) — Nico Haase, Feb 21 '19 at 12:53
is there any reason why you want to get the input as php://input ? — Vidal, Feb 21 '19 at 12:54
Yes this is executed in a CLI , I have many php with file_get_contents("php://input") — user3665736, Feb 21 '19 at 12:59
@user3665736 You can still use `file_get_contents`, just use `stdin` instead of `input`. — Yoshi, Feb 21 '19 at 13:01

Gino Pane · Answer 1 · 2019-02-21T13:01:26.560

5

Please try with stdin instead:

echo "hello" | php -r 'print_r("input content:".file_get_contents("php://stdin"));'

More about CLI streams: http://php.net/manual/en/features.commandline.io-streams.php

edited Feb 21 '19 at 13:01

answered Feb 21 '19 at 12:52

Gino Pane

4,740
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Thanks for your answer, in fact I have many php scripts using file_get_contents("php://input") and I try to figure out how to pass the info in command line – user3665736 Feb 21 '19 at 12:58
1

php://input is for request body, in command line you'll have standard input: http://php.net/manual/en/features.commandline.io-streams.php – Gino Pane Feb 21 '19 at 13:01
Yes I want to simulate a request body (some JSON string in fact) – user3665736 Feb 21 '19 at 13:10

score 0 · Answer 2 · answered Feb 21 '19 at 12:53

0

You can use the arguments.

#!/usr/bin/php
<?php
// loop through each element in the $argv array
foreach($argv as $value){
  echo "$value\n";
}

answered Feb 21 '19 at 12:53

Vidal

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score 0 · Answer 3 · answered Feb 21 '19 at 13:48

0

In fact php://input will only work if I use php-cgi instead of php So to pass a request body code is like:

echo '{"a":1}' | php-cgi -r 'print("input content:".file_get_contents("php://input"));'

answered Feb 21 '19 at 13:48

user3665736

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1
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PHP : how to retrieve piped stuff

3 Answers3