Convert binary value as string to uint32 in Golang

Question

Hello i am trying to convert 00000000000000000000000000001011 to uint32 in golang using

var v = "00000000000000000000000000001011"
fmt.Printf("%T\n", v)
c := []byte(v)
u := binary.LittleEndian.Uint32(c)

However it is not working.

Answer 1

You can't use encoding/binary for this, as that is to serialize and deserialize the (memory) bytes of different values (e.g. numbers). What you have is the base 2 string representation of the number.

To get its integer value you have to parse it. For that, use strconv.ParseUint():

s := "00000000000000000000000000001011"
u, err := strconv.ParseUint(s, 2, 32)
if err != nil {
    panic(err)
}
fmt.Println(u)

This outputs (try it on the Go Playground):

11

Note that strconv.ParseUint() returns a value of type uint64, so if you need uint32, you have to manually convert it, e.g.:

u32 := uint32(u)

There are more options for parsing numbers from strings, for an overview, check Convert string to integer type in Go?

Answer 2

For example,

package main

import (
    "fmt"
    "strconv"
)

func main() {
    s := "00000000000000000000000000001011"
    fmt.Println(s)
    u64, err := strconv.ParseUint(s, 2, 32)
    u32 := uint32(u64)
    if err == nil {
        fmt.Println(u32)
    }
}

Playground: https://play.golang.org/p/yiicgWsb7B_M

Output:

00000000000000000000000000001011
11