Is it possible to make constructor property assigment list like this make shorter?

Question

Is it possible to avoid "this" assignment list and somehow "spread" all the args named in constructor?

class MyClass {
    constructor(arg1, arg2, arg3, arg4, arg5) {
        this.arg1 = arg1;
        this.arg2 = arg2;
        this.arg3 = arg3;
        this.arg4 = arg4;
        this.arg5 = arg5;
    }

}

no matter on names - just to somehow spread args to its same or simmilar this.properties — Bambino Negro, Feb 21 '19 at 21:42
How about passing an object as the constructor parameter instead of separate arguments? — Barmar, Feb 21 '19 at 21:43
`new MyClass({ arg1: 1, arg2: "foo", ...})`? Then you can use `Object.assign()` in the constructor. — Barmar, Feb 21 '19 at 21:45
Or go with your original arguments, and use `Object.assign(this, {arg1, arg2, arg3, arg4, arg5});` — Barmar, Feb 21 '19 at 21:50
I'm not sure which comment you're linking to. But he never said it changes dynamically, just that it can change over time. When you change it, you change the `Object.assign` line accordingly. — Barmar, Feb 21 '19 at 21:56

Nina Scholz · Answer 1 · 2019-02-21T21:51:16.653

1

You could take an array of keys an iterate the arguments.

class MyClass {
    constructor(...args) {
        var keys = ['arg1', 'arg2', 'arg3', 'arg4', 'arg5']
        keys.forEach((k, i) => this[k] = args[i]);
    }
}

var instance = new MyClass('a', 'b');

console.log(instance);

edited Feb 21 '19 at 21:51

answered Feb 21 '19 at 21:45

Nina Scholz

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This is probably what @NenadVracar was thinking of. – Barmar Feb 21 '19 at 21:46
3

Might be better to iterate over `keys`, then you'll simply ignore any extra args. – Barmar Feb 21 '19 at 21:47
Barnar - write as a comment so I could flag it as correct answer – Bambino Negro Feb 22 '19 at 02:05

Is it possible to make constructor property assigment list like this make shorter?

1 Answers1