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I have the following string:

redis. 600 IN A 172.16.0.3 redis. 600 IN A 172.16.0.4 redis. 600 IN A 172.16.0.5 redis. 600 IN A 172.16.0.6 redis. 600 IN A 172.16.0.7

The string is obtained from the following command: 

dig redis A | grep redis | grep -E '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}'

The string is printed out on each line when the command is run, but I save the output to a variable so it's all one line. I want to get all of the IP addresses into a bash array. What's the best way for me to do this?

Edit: This post is not a duplicate because the focus of this was how to get the IP addresses, not how to read them into the array.

AndreasKralj
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  • If you show the file after dig command and add awk in the tag of your question, I'm sure you get a better answer. – ctac_ Feb 22 '19 at 17:44

1 Answers1

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I ended up being able to do it by using awk:

IPAddresses=($(dig redis A | grep redis | grep -E '[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}' | awk '{print $5}'))

The IPAddresses array has all of the IP addresses in it, and can be printed out by executing echo "${IPAddresses[@]}"

AndreasKralj
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