I'm trying to search files for specific text. Then print the line immediately prior to the line, and all subsequent lines that start with a specific character, particularly a 'space.'
Here's a sample of the file I'm trying to read:
interface vlan 22
ip address 10.10.2.1 255.255.255.0
ip helper-address 10.10.44.1
ip helper-address 10.10.44.2
!
interface vlan 23
ip address 10.10.23.1 255.255.255.0
ip helper-address 10.10.44.1
ip helper-address 10.10.44.2
!
When I see 'IP address' I want to print the line immediately prior, and then all the configuration items under that interface.
Currently, I'm reading from a directory of files and outputting specific information from the files. Here's the code:
for file in glob.glob('*.log'):
with open(file) as search:
with open(queryoutput,"a") as foutput:
for line in search:
line = line.rstrip()
if hostcheck in line:
hostentry = line.split("hostname ")[1]
foutput.write("Subnet information below is from " + hostentry + "\n")
elif ipaddress in line:
foutput.write("Local Device: " + hostentry + "\n")
foutput.write("Remote " + line + "\n")
Not all network devices will state "interface" in the VLAN line, so that's why I don't want to search for that text, and there's not a guarantee an exclamation would be the last item, though it's highly probable. That's why I'm looking for a way to read the lines based on 'IP address' and spaces.
I'm still new to Python, and programming in general, but it looks like something like this might help. I'm just not fully understanding how that would work.
Any thoughts on how I can accomplish this? Also, I'm trying to use Python 3.x.