18

Take this example:

>>> 5+10
15
>>> a = 5 + 10
>>> a
15

How and why does Python do this without an explicit print statement?

If I do the same thing in an IPython cell, only the last such value is actually printed on stdout in this way:

In[1]: 5+10
       1

Out[1]: 1

Why does this happen?

Peter Mortensen
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Chayan Ghosh
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2 Answers2

35

When Python is in "interactive" mode, it enables certain behaviors it doesn't have in non-interactive mode. For example, sys.displayhook, originally specified in PEP 217.

If value is not None, this function prints it to sys.stdout, and saves it in __builtin__._.

sys.displayhook is called on the result of evaluating an expression entered in an interactive Python session.

You can modify this behavior:

>>> import sys
>>> def shook(expr):
...   print(f'can haz {expr}?')
...
>>> sys.displayhook = shook
>>> 123
can haz 123?
>>> False
can haz False?
>>> None
can haz None?

And also set it back to normal:

>>> sys.displayhook = sys.__displayhook__
>>> 3
3

In the default Python repl, sys.displayhook is

>>> import sys;
>>> sys.displayhook
<built-in function displayhook>

but in IPython it's

In [1]: import sys

In [2]: sys.displayhook
Out[2]: <IPython.terminal.prompts.RichPromptDisplayHook at 0x7f630717fa58>

So that's why you see different behavior between Python and IPython.

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kojiro
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2

That's how all interpreters work. They don't need any print, but one thing, and without print they do the repr of everything, and print doesn't, example:

>>> 'blah'
'blah'
>>> print('blah')
blah
>>>

Look at the quotes.

Also see this:

>>> print(repr('blah'))
'blah'
>>>

repr does the same.

Peter Mortensen
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